Created
March 11, 2012 03:55
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#!/usr/bin/env ruby1.9 | |
# Project Euler, Problem 12 | |
# | |
# The sequence of triangle numbers is generated by adding the natural | |
# numbers. So the 7th triangle number would be 1 + 2 + 3 + 4 + 5 + 6 + 7 = | |
# 28. The first ten terms would be: | |
# | |
# 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, ... | |
# | |
# Let us list the factors of the first seven triangle numbers: | |
# | |
# 1: 1 | |
# 3: 1,3 | |
# 6: 1,2,3,6 | |
# 10: 1,2,5,10 | |
# 15: 1,3,5,15 | |
# 21: 1,3,7,21 | |
# 28: 1,2,4,7,14,28 | |
# | |
# We can see that 28 is the first triangle number to have over five divisors. | |
# | |
# What is the value of the first triangle number to have over five hundred | |
# divisors? | |
# | |
# Lawrence Velazquez | |
# 10 March 2012 | |
class Integer | |
def divisors | |
divs = [1, self] | |
2.upto(Math.sqrt(self)) {|i| divs.concat [i, self / i] if self % i == 0} | |
divs | |
end | |
end | |
i = 1 | |
ans = while true | |
tri_n = i * (i + 1) / 2 | |
break tri_n if tri_n.divisors.count > 500 | |
i += 1 | |
end | |
puts ans |
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