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July 19, 2025 09:18
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Collapsed LUYH Equation Complex Resolve
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| # Collapsed LUYH Equation Complex Set Solution: | |
| # The mind bending modulus solve luyh equation done with slots & list comprehensions | |
| # and+ collapsed forced n-resolves. Use of paired numbers @iks more probable returns | |
| # of -1. If you need the specific luyh series number found set returnLuyhSeries=True. | |
| # Is computational intense and needs to be placed in a multi-processing distinction. | |
| # (Solid use for top-grade trignometric encryption solutions involving seq-erroring) | |
| #_______________________________________________________________________________________ | |
| import cmath | |
| import math | |
| #_______________________________________________________________________________________ | |
| class COLLAPSED_LUYH(): | |
| slots = ['_lstA', '_lstB', '_lstC', '_lstD', '_lstE', '_lstDrd1', '_lstDrd2', | |
| '_lstLe1', '_iks1', '_intA', '_intB', '_intC', '_strA', '_blnA'] | |
| def __init__(self): | |
| pass | |
| #_______________________________________________________________________________________ | |
| def rotate_pair(self, p: tuple, k_chr: str) -> tuple: | |
| if k_chr == 'L': | |
| return (p[1], p[0]) | |
| elif k_chr == 'U': | |
| return (p[0]+1, p[1]+1) | |
| elif k_chr == 'Y': | |
| return p | |
| elif k_chr == 'H': | |
| return (p[0]-1, p[1]-1) | |
| else: | |
| return p | |
| #_______________________________________________________________________________________ | |
| def drhl_distribute(self, isRtn: bool, n: int) -> tuple: | |
| if n == 0: | |
| return [[]] | |
| else: | |
| self._lstA = self.drhl_distribute(isRtn, n-1) | |
| self._lstB = [(complex(math.floor(math.sqrt((self._intB**self._intC)/(math.pi**3))), self._intB+1), complex(math.floor(math.sqrt((self._intB+self._intC)/(self._intC*math.pi))), self._intC-1)) for self._intB in range(1, self._intA+1) for self._intC in range(1, self._intA+1)] | |
| self._lstC = [self.rotate_pair(self._lstD, self._iks1[self._intB%len(self._iks1)]) for self._intB, self._lstD in enumerate(self._lstB)] | |
| if isRtn: | |
| return self._lstA+self._lstC | |
| else: | |
| return self._lstB+self._lstA | |
| #_______________________________________________________________________________________ | |
| def luyh_resolve(self, isReassemble: bool, halfLoopMode: int): | |
| if isReassemble: | |
| self._lstLe1 = list(set([(cmath.sqrt(self._intB[0]*cmath.pi**self._intB[1])-self._intC[1])/cmath.acos(self._intC[0]*self._intB[1]*math.pi) for self._intB in self._lstDrd1 for self._intC in self._lstDrd2])) | |
| else: | |
| if halfLoopMode == 2: | |
| self._lstLe1 = [(abs(self._intB.real)-abs(self._intB.imag))*(math.cos(self._intB.real+math.pi)**math.sqrt(self._intB.imag+math.pi)) for self._intB in self._lstLe1] | |
| else: | |
| self._lstLe1 = [(((math.sin(self._intB.real+self._intB.imag-math.pi)/math.sqrt(math.pi*4))*math.pi)%(self._intA-self._intB.imag-self._intB.real))/math.pi for self._intB in self._lstLe1] | |
| #_______________________________________________________________________________________ | |
| def check_iks_and_n(self, iks: str, n: int): | |
| self._intA = n | |
| if isinstance(iks, str) and isinstance(n, int): | |
| if n > 5: | |
| raise Exception(f'<luyh err> invalid param @n={n}, impossible without a quantum computer; 1-5 valid @n') | |
| else: | |
| raise Exception('<luyh err> invalid luyh equation set params; iks<str> & n<int> are valid params only') | |
| #_______________________________________________________________________________________ | |
| def set_iks(self): | |
| self._lstA = [] | |
| for self._strA in iks: | |
| if self._strA == '1': self._lstA.append('L') | |
| elif self._strA == '2': self._lstA.append('U') | |
| elif self._strA == '3': self._lstA.append('Y') | |
| elif self._strA == '4': self._lstA.append('H') | |
| else: | |
| raise Exception(f'<luyh err> invalid iks sequence, ({self._strA}) not a 1-4 digit') | |
| self._iks1 = ''.join(self._lstA) | |
| #_______________________________________________________________________________________ | |
| def luyh_half_loops_operator(self, returnLuyhSeries: bool, iks: str, n: int): | |
| self.check_iks_and_n(iks, n) | |
| try: | |
| self._lstE, self._iks1, self._bln = [], iks, True | |
| while 1: | |
| if self._bln: self._bln = False | |
| else: | |
| if len(self._iks1) > 1: | |
| self._iks1 = self._iks1[1:len(self._iks1)-1] | |
| else: | |
| break | |
| self._lstDrd1 = self.drhl_distribute(True, self._intA) | |
| self._lstDrd1.pop(0) | |
| self._lstDrd2 = self.drhl_distribute(False, self._intA) | |
| self._lstDrd2.pop(len(self._lstDrd2)-1) | |
| self.luyh_resolve(True, 1) | |
| self.luyh_resolve(False, 2) | |
| self.luyh_resolve(False, 4) | |
| self._lstE.append(math.trunc(sum(self._lstLe1))) | |
| self._intB = sum(self._lstE) | |
| self._intC = math.floor((self._intB*max(self._lstE)*min(self._lstE)*(self._intA+min(self._lstE)))*((self._intA*max(self._lstE))*self._intA)) | |
| if self._intC%self._intB == 0: | |
| if not returnLuyhSeries: | |
| return self._intB | |
| else: | |
| return (self._intC, self._intB) | |
| else: | |
| return -1 | |
| except Exception as lattice_luyh_iks_pair: | |
| return -1 | |
| #_______________________________________________________________________________________ | |
| def luyh_resolve(returnLuyhSeries: bool, iks: str, n: int): | |
| cls = COLLAPSED_LUYH() | |
| return cls.luyh_half_loops_operator(returnLuyhSeries, iks, n) | |
| #_______________________________________________________________________________________ | |
| def test(): | |
| # luyh keys are 1-4 just as LtoR or RtoL count on a Menorah center; also yo hands | |
| print(luyh_resolve(True, '434123421444312321421', 5)) | |
| test() |
Author
Author
Secondly, the quantum version of the LUYH Equation, n being greater than 5. That requires triple recursion inside a specific type of vector bracketing. Once at n=6 then is all half-loops whole and a classical computer cannot perform.
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Okay. First, the LUYH Equation is a very hard trigonometric problem to solve with large iks keys, both this version that doesn't need the key to be 1-4 specifically chars or the non-forced real rotational based LUYH Equation resolve that must be 1-4 chars. Of sequence erroring use you would typically splice in end to ends or begin to begins with a known standard LUYH Equation solve of rotation erroring. Thus, you can use this version hidden of it's specific use yet still have a length to length solve. Both variations are based on Menorah half-loop complex rotational solves.