Created
August 9, 2014 10:12
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Convert case class to map in Scala
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| def ccToMap(cc: AnyRef) = | |
| (Map[String, Any]() /: cc.getClass.getDeclaredFields) { | |
| (a, f) => | |
| f.setAccessible(true) | |
| a + (f.getName -> f.get(cc)) | |
| } | |
| // Usage | |
| case class Column(name: String, | |
| typeCode: Int, | |
| typeName: String, | |
| size: Int = 0) | |
| val column = Column("id", 0, "INT", 11) | |
| println(ccToMap(column)) |
Kudos.
This is great
Hi if i want to do reverse of it... Like i have a map of column names and datatypes creating a case class?
very useful
thanks
def ccToMap(cc: AnyRef) = cc.getClass.getDeclaredFields.foldLeft (Map.empty[String, Any]) { (a, f) => f.setAccessible(true) a + (f.getName -> f.get(cc)) }
def productToMap(cc: Product) = cc.productElementNames.zip(cc.productIterator).toMap
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Really useful, thank you !!