A well-known interview question, FizzBuzz Problem's solution.

FizzBuzz.js

for (var i = 0; i <= 100; i++) {
    if (i % 3 == 0 && i % 5 == 0) {
        console.log('FizzBuzz')
    } else if (i % 3 == 0) {
        console.log('Fizz')
    } else if (i % 5 == 0) {
        console.log('Buzz')
    } else {
        console.log(i)
    }
}