Created
April 3, 2013 17:41
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Bitstring DP for the checkerboard problem http://www.reddit.com/r/math/comments/1bksoo/what_is_your_favorite_logic_or_math_puzzle/c97ots6
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| def gi(n,i): | |
| return n&(1<<i) | |
| def b(n): | |
| l = [] | |
| for k in filter(lambda n: n%5 < 4, range(19)): | |
| if gi(n,k) and not gi(n,k+1) and not gi(n,k+5): | |
| l.append(k) | |
| return l | |
| def transition(n, k): | |
| return n - (1<<k) + (1<<(k+1)) + (1<<(k+5)) | |
| def valid(n): | |
| return not (n&1127) | |
| def ln(n): | |
| x = 0 | |
| for k in range(25): | |
| if n&(1<<k): | |
| x += 1 | |
| return x | |
| O = {} | |
| # n, n -> () | |
| def DP(n, left): | |
| if n in O: | |
| return | |
| if not left: | |
| return | |
| if valid(n): | |
| print n | |
| return | |
| O[n] = b(n) | |
| for k in O[n]: | |
| m = transition(n,k) | |
| DP(m, left-1) | |
| return | |
| def p(n): | |
| s = (("%s "*5) + "\n")*5 | |
| x = [] | |
| for k in range(25): | |
| x.append('x' if n&(1<<k) else ' ') | |
| print s%tuple(x) | |
| DP(1,30) | |
| l = sorted([(n, ln(n)) for n in O], key=lambda p: p[1]) | |
| def hm(k): | |
| return filter(lambda p: p[1] == k, l) | |
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