Lee Gao leegao
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| \documentclass[12pt,a4paper,svgnames]{article} | |
| \usepackage{amsmath} | |
| \usepackage{fullpage} | |
| \usepackage{amsfonts} | |
| \usepackage{amssymb,amsthm} | |
| \usepackage{makeidx} | |
| \usepackage{graphicx} | |
| \usepackage{float} | |
| \usepackage{wrapfig} | |
| \usepackage{algorithm} |
leegao
/ EllipseZero.m
Last active
December 16, 2015 07:49
Finding the quadrants on which an ellipse resides upon
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| function [ x1,x2,y1,y2 ] = FindQuad( a,b,h,k,phi ) | |
| %FINDQUAD Summary of this function goes here | |
| % Detailed explanation goes here | |
| x = @(t) h + cos(phi)*a*cos(t) - sin(phi)*b*sin(t); | |
| y = @(t) k + sin(phi)*a*cos(t) + cos(phi)*b*sin(t); | |
| t = 0:0.05:2*pi; | |
| subplot(3,1,1); | |
| plot(x(t),y(t)) | |
| axis equal | |
leegao
/ dp.py
Created
April 3, 2013 17:41
Bitstring DP for the checkerboard problem http://www.reddit.com/r/math/comments/1bksoo/what_is_your_favorite_logic_or_math_puzzle/c97ots6
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| def gi(n,i): | |
| return n&(1<<i) | |
| def b(n): | |
| l = [] | |
| for k in filter(lambda n: n%5 < 4, range(19)): | |
| if gi(n,k) and not gi(n,k+1) and not gi(n,k+5): | |
| l.append(k) | |
| return l |
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| type var = string;; | |
| type ar = Int of int | Var of var | Add of ar * ar;; | |
| type bl = True | False | And of bl * bl | Or of bl * bl | Eq of ar * ar | Le of ar * ar;; | |
| type com = Skip | Assgn of var * ar | Seq of com * com | If of bl * com * com | While of bl * com | Break;; | |
| (* representation for stores *) | |
| module Store = Map.Make(struct | |
| type t = var | |
| let compare = Pervasives.compare | |
| end) |
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| open Ast | |
| exception TypeError | |
| exception UnificationError | |
| (* ---------- EQUALITY ---------- *) | |
| (* [typ_eq t1 t2] returns [true] iff [t1] and [t2] are equal *) | |
| let rec typ_eq (t1:typ) (t2:typ) : bool = | |
| match t1,t2 with |
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| def pthing(title,ext,n): | |
| overlay = ''' | |
| <GroundOverlay> | |
| <name>res</name> | |
| <TimeSpan> | |
| <begin>%s</begin> | |
| <end>%s</end> | |
| </TimeSpan> | |
| <Icon> |
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| function swinger(x0,y0,m1,m2,l1,l2) | |
| % SWINGER Classic double pendulum. | |
| % SWINGER(x,y) starts the pendulum at the given initial position. | |
| % The initial position can reset with the mouse. | |
| % | |
| % SWINGER with no arguments starts at (x,y) = (0.862,-0.994). | |
| % What is interesting about the resulting orbit? | |
| % | |
| % SWINGER(0,2) starts in an unstable vertical position. | |
| % How long does it stay there and what causes it to move? |
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| #include <windows.h> | |
| #include <stdio.h> | |
| //68 BE BA FE CA | |
| const unsigned char OP_PUSH = 0x68; | |
| const unsigned char OP_JMP = 0xE9; | |
| static DWORD rets[10000]; | |
| static PDWORD r = NULL; | |
| struct patchwork{ |
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| open Ast | |
| (* lexp_of_aexp: convert an aexp into an lexp *) | |
| let rec lexp_of_aexp (a:aexp) : lexp = | |
| match a with | |
| | Int n -> | |
| LInt n | |
| | Var x -> | |
| LPVar x | |
| | Plus(a1,a2) -> |
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| <html> | |
| <head> | |
| <title>Scrolling Cards</title> | |
| <script src="http://code.jquery.com/jquery-1.8.1.min.js"></script> | |
| <script type="text/javascript"> | |
| jQuery.fn.center = function () { | |
| this.css("position","absolute"); | |
| this.css("bottom", "1px");// Math.max(0, (($(window).height() - this.outerHeight()) / 2) + | |
| // $(window).scrollTop()) + "px"); | |
| this.css("left", Math.max(0, (($(window).width() - this.outerWidth()) / 2) + |