Created
December 7, 2018 08:38
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高效率的幂运算
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| long long pow(long long x, int n) { | |
| if (n == 0) | |
| return 1; | |
| if (n == 1) | |
| return x; | |
| if (n & 0x1) | |
| return pow(x * x, n / 2) * x; | |
| else | |
| return pow(x * x, n / 2); | |
| } |
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