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May 28, 2019 13:49
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二分查找的不完全总结
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/* | |
* 1. right = nums.size() | |
* 2. left < right | |
* 3. right = mid | |
* 4. return right | |
*/ | |
int find(vector<int> &nums, int target) { | |
int left = 0, right = nums.size(); | |
while (left < right) { | |
int mid = left + (right - left) / 2; | |
if (nums[mid] < target) | |
left = mid + 1; // [1, 2, 3, 4, 5] 排除 1 2 3 left = 4 | |
else | |
right = mid; | |
} | |
return -1; | |
} | |
int low_bound(vector<int> &nums, int target) { | |
int left = 0, right = nums.size(); | |
while (left < right) { | |
int mid = left + (right - left) / 2; | |
if (nums[mid] < target) | |
left = mid + 1; | |
else | |
right = mid; // [0, 1, 1, 1, 1] mid >= target 排除右半边 | |
} | |
return right; | |
} | |
int up_bound(vector<int> &nums, int target) { | |
int left = 0, right = nums.size(); | |
while (left < right) { | |
int mid = left + (right - left) / 2; | |
if (nums[mid] <= target) // [0, 1, 1, 1, 1] 排除左半边 | |
left = mid + 1; | |
else | |
right = mid; | |
} | |
return right; | |
} |
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