Created
April 20, 2012 02:44
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puzzle #2
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| import sys | |
| import math | |
| # yes, stolen from wikipedia. | |
| def binomialCoefficient(n, k): | |
| if k < 0 or k > n: | |
| return 0 | |
| if k > n - k: # take advantage of symmetry | |
| k = n - k | |
| c = 1 | |
| for i in range(k): | |
| c = c * (n - (k - (i+1))) | |
| c = c // (i+1) | |
| return c | |
| def hypergeometric(N, m, n, k): | |
| a = binomialCoefficient(m, k) | |
| b = binomialCoefficient(N-m, n-k) | |
| c = binomialCoefficient(N, n) | |
| return a * b * 1.0 / c | |
| if __name__ == '__main__': | |
| m, n, t, p = [int(x) for x in sys.stdin.readline().split()] | |
| # how many of our friends must win? | |
| w = int(math.ceil(p * 1.0 / t)) if p > t else 1 | |
| # hypergeometric distribution | |
| pr = sum(hypergeometric(m, p, n, i) for i in xrange(w, p+1)) | |
| print '%.10f' % pr |
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