Safe hash comparison

comparehash.py

from itertools import izip
def compare_hash(hashone,hashtwo):
    if len(hashone) == len(hashtwo):  # Every hash should be the same length
        if sum((ord(o) ^ ord(t) for o,t in izip(hashone,hashtwo))):
            return False
        else:
            return True
    else:
        return False

I agree, I just wrote this in a verbose manner so people will understand the goal behind the code.