:uid: anisotropic-conductivity :title: Anisotropic Conductivity :description: when electrical conductivity varies with direction :tooltip: None :tag: conductivity,anisotropy,dc,em,physical properties :group: simpeg :license: CC-BY-4.0 :source: https://api.github.com/gists/56c47e9a872aa908705d
When a physical property of a material varies with direction, that material is anisotropic (not to be confused with heterogeneity. Check out Matt Hall's discussion on anisotropy). Anisotropy in electrical conductivity can have a variety of causes. To name a few:
- alignment of cracks or pores,
- bedding / lamination,
- alignment of mineral grains.
Any of these, or similar phenomena can create preferential directions
for current to flow. To examine this a bit, lets look at the constitutive relation that relates the current density
In an isotropic medium,
In an anisotropic medium,
Lets break this down and consider a few examples. Since drawing vectors and such is easier in 2D, lets consider a 2D example, where everything is happening in the x-z plane. In the figure below, we have a "rock" that is blue and gray.
The blue regions are conductive and the gray regions are resistive. If we apply an electric field in the x-direction, the charges have a choice to either go through the resistive or conductive region, like a parallel circuit. If instead we apply an electric field in the z-direction, the charges have no choice which medium they can go through.
If we want to describe the conductivity of this rock, we use a
If we excite this with an electric field oriented in the
$$ \vec{J}_{1}
$$
In a similar vein, if we use an electric field oriented in the
$$ \vec{J}_{2}
$$
So we can multiply a matrix and a vector! Thats not why I am showing you this... lets have a look at the magnitude of the current density in each case. For the first case, we have that
and in the second case,
For the example here, we know that \sigma_{xx} > \sigma_{zz}. So if the magnitude of the inducing field is identical in both cases, the resulting current density magnitude is different between the two, namely $|\vec{J}{1}| > |\vec{J}2|$. So if we wanted the current density to be same, we need to apply a bigger push in the $z$-direction; in particular, we would need: $E{z} = \sigma{xx}/\sigma_{zz} E_x$.
In this example, everything lined up with our coordinate system, so the various components didn't talk to each other. Lets change that.
I started planning on writing this about the behavior of anisotropy in cylindrically symmetric settings, but got a bit sidetracked. Anyways, that will come at another time!
http://www.agilegeoscience.com/blog/2015/2/9/what-is-anisotropy