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@libswan
Last active December 17, 2015 12:08
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Isn't there a way to programmatically figure out the connections? E.g. Instead of "telling the program" that node[0] connects with node[1], because the position of 'A' in these two nodes is position 0, can't we figure it out programmatically?
nodeNameList = []
for i in nodes:
nodeName = Node.getName(i)
nodeNameList.append(nodeName)
print nodeNameList
for n in nodeNameList[0]:
if nodeNameList[0].index(n) == nodeNameList[1].index(n):
connectionLetter = n
print connectionLetter
"""This is just comparing node element 1 (at position 0) to the next node element. But how would I compare the letters in one node element to the letters in all other node elements?"""
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