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动态规划-简易背包问题
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#include <stdlib.h> | |
#include <stdio.h> | |
// 千里码刷题: http://www.qlcoder.com/task/7566 | |
static const int goods[16] = {0, 509, 838, 924, 650, 604, 793, 564, 651, 697, 649, 747, 787, 701, 605, 644}; | |
#define MAX(x, y) ((x) > (y)? (x) : (y)) | |
int main(int argc, char * argv[]) | |
{ | |
int sum[5001] = {0}; | |
for (int i = 1; i <= 15; i++) { | |
for (int j = 5000; j >= 1; j--) { | |
if (j >= goods[i]) { | |
sum[j] = MAX(sum[j], sum[j - goods[i]] + goods[i]); | |
} | |
} | |
} | |
printf("max value %d\n", sum[5000]); | |
int max = sum[5000]; | |
for (int i = 15; i >= 1; i--) { | |
if (max >= goods[i]) { | |
if ((sum[max] - sum[max - goods[i]]) == goods[i]) { | |
printf("No.%d selected\n", i + 1); | |
max -= goods[i]; | |
} | |
} | |
} | |
system("pause"); | |
return 0; | |
} |
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