Created
May 25, 2015 08:56
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「Five programming problems every Software Engineer should be able to solve in less than 1 hour」をrubyで解いてみた
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# encoding: sjis | |
# 1 | |
# using for | |
def sum_for(list) | |
sum = 0 | |
for i in list | |
sum += i | |
end | |
sum | |
end | |
# using while | |
def sum_while(list) | |
sum = 0 | |
i = 0 | |
while i < list.length | |
sum += list[i] | |
i += 1 | |
end | |
sum | |
end | |
# using recursive call | |
def sum_rec(list, sum=0) | |
return sum if list.empty? | |
head = list.shift | |
sum_rec(list, sum + head) | |
end | |
# 2 | |
def my_zip(alist=[], blist=[], result=[]) | |
return result if alist.empty? && blist.empty? | |
a = alist.shift | |
b = blist.shift | |
my_zip(alist, blist, (result << [a, b].compact).flatten) | |
end | |
# 3 | |
def fib(n) | |
case n | |
when 0 | |
[] | |
when 1 | |
[0] | |
else | |
list = [0, 1] | |
(n - list.length).times do | |
list[list.length] = list[-2] + list[-1] | |
end | |
list | |
end | |
end | |
# 4 | |
def perm_max(list=[]) | |
list.permutation.collect{ |i| i.map(&:to_s).join }.max.to_i | |
end | |
# 5 | |
def comb_100(size=1) | |
["+", "-", ""] | |
.repeated_permutation(size - 1) | |
.to_a | |
.map{ |e| (1..size).to_a.zip(e).flatten.map(&:to_s).join } | |
.select{ |e| eval(e) == 100 } | |
end |
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