Created
          April 24, 2018 15:46 
        
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    Solution for reversing an integer
  
        
  
    
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  | func reverse(x int) int { | |
| neg := 1 | |
| ans := 0 | |
| if x < 0 { | |
| //make sure to only work with positive numbers | |
| x *= -1 | |
| neg = -1 | |
| } | |
| //the business loop! | |
| for x > 0 { | |
| ans *= 10 | |
| ans += x %10 | |
| x = x/10 | |
| } | |
| //catch overflow | |
| if ans > 2147483648 || ans < (2147483648 * -1) { | |
| return 0 | |
| } | |
| return ans * neg | |
| } | 
  
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