Created
March 22, 2019 16:50
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Choose optimal way to multiply matrices.
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#include <iostream> | |
#include <iomanip> | |
#include <string> | |
#include <vector> | |
#include <utility> | |
#include <limits> | |
#include <cstdint> | |
using Matrix = std::vector<std::vector<int>>; | |
auto matrixChainOrder(const std::vector<int>& p) | |
{ | |
int n = p.size(); | |
Matrix m{}; | |
m.resize(n); | |
for(int i = 0; i < n; i++) | |
{ | |
m[i].resize(n); | |
} | |
Matrix s{}; | |
s.resize(n - 1); | |
for(int i = 0; i < n - 1; i++) | |
{ | |
s[i].resize(n); | |
} | |
for (int i = 0; i < n; i++) | |
{ | |
m[i][i] = 0; | |
} | |
for(int l = 2; l < n; l++) | |
{ | |
for(int i = 1; i < n - l + 1; i++) | |
{ | |
int j = i + l - 1; | |
// m[i][j] = std::numeric_limits<int>::max(); | |
m[i][j] = 0; | |
m[i][j] = ~m[i][j]; | |
m[i][j] = (unsigned int)m[i][j] >> 1; | |
for(int k = i; k <= j - 1; k++) | |
{ | |
int q = | |
m[i][k] + m[k + 1][j] + p[i - 1] * p[k] * p[j]; | |
if (q < m[i][j]) | |
{ | |
m[i][j] = q; | |
s[i][j] = k; | |
} | |
} | |
} | |
} | |
return std::make_pair(m, s); | |
} | |
void printOptimalParens(Matrix s, int i, int j) | |
{ | |
if(i == j) | |
{ | |
std::cout << "A" << i; | |
} | |
else | |
{ | |
std::cout << "("; | |
printOptimalParens(s, i, s[i][j]); | |
printOptimalParens(s, s[i][j] + 1, j); | |
std::cout << ")"; | |
} | |
} | |
int main() | |
{ | |
std::vector<int> shapes {12, 12, 12, 24, 24, 25, 25, 13, 13, 11, 11, 12}; | |
auto [m, s] = matrixChainOrder(shapes); | |
for(int i = 0; i < m.size(); i++) | |
{ | |
for(int j = 0; j < m[i].size(); j++) | |
{ | |
std::cout << std::setw(10) << m[i][j] << ' '; | |
} | |
std::cout << '\n'; | |
} | |
for(int i = 0; i < s.size(); i++) | |
{ | |
for(int j = 0; j < s[i].size(); j++) | |
{ | |
std::cout << s[i][j] << ' '; | |
} | |
std::cout << '\n'; | |
} | |
printOptimalParens(s, 1, 6); | |
return 0; | |
} |
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