Created
May 7, 2014 13:31
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Haskell Implementation of Split At
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| seperateAt :: Int -> [a] -> ([a],[a]) | |
| seperateAt 0 [] = ([], []) | |
| seperateAt 0 xs = ([], xs) | |
| seperateAt n (x: []) = (x : [], []) | |
| seperateAt n (x:xs) = | |
| let result = (seperateAt (n - 1) xs) | |
| in (x : fst result, snd result) |
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