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June 15, 2015 15:57
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BZOJ 1117: [POI2009]救火站Gas
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#include<cstdio> | |
#include<vector> | |
#include<algorithm> | |
using namespace std; | |
const int kN = 1e5+10; | |
const int kK = 20+2; | |
int N, S, K; | |
vector<int> G[kN]; | |
long long need[kN][kK], have[kN][kK]; | |
int deep[kN], fa[kN]; | |
int ans = 0; | |
void DFS(int u, int fa_) { | |
deep[u] = deep[fa_]+1; | |
fa[u] = fa_; | |
for (int i = 0; i < G[u].size(); i++) { | |
int v = G[u][i]; | |
if (v == fa_) continue; | |
DFS(v, u); | |
for (int j = 0; j < K; j++) need[u][j+1] += need[v][j]; | |
for (int j = 1; j <= K; j++) have[u][j-1] += have[v][j]; | |
} | |
need[u][0]++; | |
long long t = need[u][K]-have[u][K]; | |
if (t > 0) { | |
int cnt = t/S; | |
if (t%S) cnt++; | |
have[u][K] += cnt*S; | |
ans += cnt; | |
} | |
for (int j = 0; j <= K; j++) { | |
for (int k = j; k >= 0 && k >= j-1; k--) { | |
int d = min(need[u][k], have[u][j]); | |
need[u][k] -= d; | |
have[u][j] -= d; | |
} | |
} | |
} | |
int main() { | |
//freopen("in.txt", "r", stdin); | |
scanf("%d %d %d", &N, &S, &K); | |
for (int i = 1; i <= N-1; i++) { | |
int u, v; scanf("%d %d", &u, &v); | |
G[u].push_back(v); | |
G[v].push_back(u); | |
} | |
DFS(1, 0); | |
for (int i = 0; i <= K; i++) { | |
for (int j = 0; j <= i; j++) { | |
int d = min(have[1][i], need[1][j]); | |
have[1][i] -= d; | |
need[1][j] -= d; | |
} | |
} | |
int t = 0; | |
for (int i = 0; i <= K; i++) t += need[1][i]; | |
ans += t/S; | |
if (t%S) ans++; | |
printf("%d\n", ans); | |
return 0; | |
} |
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