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June 16, 2015 07:48
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BZOJ 3203: [Sdoi2013]保护出题人
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#include<cstdio> | |
#include<algorithm> | |
using namespace std; | |
typedef long long LL; | |
typedef long double LD; | |
const int kN = 1e5+10; | |
int N; | |
LL D; | |
LL A[kN], X[kN], SUM[kN]; | |
struct Queue{ | |
int a[kN], q_s, q_t; | |
void Init(int n) { | |
q_t = n; | |
q_s = n+1; | |
} | |
int Size() { | |
return q_t-q_s+1; | |
} | |
void PopFront() { | |
q_s++; | |
} | |
void PushFront(int v) { | |
a[--q_s] = v; | |
} | |
int & operator [] (int i) { | |
return a[q_s+i]; | |
} | |
}Q; | |
void TestQueue() { | |
Q.Init(10); | |
Q[0] = 8; | |
printf("%d\n", Q[0]); | |
} | |
LD Slope(int i, int j) { | |
LD x = (i-j)*D; | |
LD y = SUM[j]-SUM[i]; | |
return y/x; | |
} | |
LD CalcAns(int n, int i) { | |
LD dis = X[n]+(n-i)*D; | |
LD sum = SUM[i]-SUM[n+1]; | |
return sum/dis; | |
} | |
int main() { | |
//TestQueue(); | |
//freopen("in.txt", "r", stdin); | |
scanf("%d %lld", &N, &D); | |
for (int i = 1; i <= N; i++) { | |
scanf("%lld %lld", A+i, X+i); | |
} | |
for (int i = N; i >= 1; i--) { | |
SUM[i] = SUM[i+1]+A[i]; | |
} | |
LD ans = 0; | |
Q.Init(N); | |
for (int i = 1; i <= N; i++) { | |
while (Q.Size() > 1 && Slope(i, Q[0]) <= Slope(Q[0], Q[1])) { | |
Q.PopFront(); | |
} | |
Q.PushFront(i); | |
int l = 0, r = Q.Size()-1; | |
while (r-l >= 3) { | |
int d = (r-l)/3; | |
int mid1 = l+d; | |
int mid2 = l+d*2; | |
LD v1 = CalcAns(i, Q[mid1]); | |
LD v2 = CalcAns(i, Q[mid2]); | |
if (v1 < v2) l = mid1; | |
else r = mid2; | |
} | |
LD tmp = 0; | |
for (int j = l; j <= r; j++) { | |
tmp = max(tmp, CalcAns(i, Q[j])); | |
} | |
ans += tmp; | |
//printf("solved : %d ans = %.10Lf\n", i, ans); | |
} | |
printf("%.0Lf\n", ans); | |
//printf("%lld\n", LL(ans)); | |
return 0; | |
} |
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