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Redirect stdout to a file in python using with block
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import sys | |
class stdio_redirect: | |
def __init__(self, stdin=None, stdout=None, stderr=None): | |
self.stdin, self.sys_stdin = stdin, sys.stdin | |
self.stdout, self.sys_stdout = stdout, sys.stdout | |
self.stderr, self.sys_stderr = stderr, sys.stderr | |
def __enter__(self): | |
sys.stdin = self.stdin | |
sys.stdout = self.stdout | |
sys.stderr = self.stderr | |
return self.sys_stdin, self.sys_stdout, self.stderr | |
def __exit__(self, exc_type, exc_value, traceback): | |
sys.stdin = self.sys_stdin | |
sys.stdout = self.sys_stdout | |
sys.stderr = self.sys_stderr | |
if __name__ == '__main__': | |
with stdio_redirect(stdout=sys.stderr, stderr=sys.stdout) as (f0, f1, f2): | |
print("1: stderr") | |
print("2: stdout", file=sys.stderr) | |
print("3: stdout", file=f1) | |
print("4: stdout") | |
print("5: stderr", file=sys.stderr) |
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