Last active
April 28, 2018 19:27
-
-
Save lovasoa/40d6a429f9599f1c6c89366485b3bdaf to your computer and use it in GitHub Desktop.
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
CREATE TABLE SUBJECT1 ( | |
NAME VARCHAR(100), | |
SURNAME VARCHAR(100), | |
CITY VARCHAR(100) | |
); | |
INSERT INTO SUBJECT1 | |
SELECT NAME, SURNAME, CITY | |
FROM SUBJECT | |
GROUP BY NAME, SURNAME, CITY; | |
SELECT | |
AGREEMENT.VID_STRAHOVANIYA, | |
100 * COUNT( | |
CHILD.DATESTART >= '2017-01-01' | |
AND | |
CHILD.DATESTART <= '2017-12-31' | |
) / COUNT(*) | |
FROM AGREEMENT | |
INNER JOIN AGREEMENT | |
ON CHILD.PARENTISN = AGREEMENT.ISN | |
GROUP BY AGREEMENT.VID_STRAHOVANIYA; | |
UPDATE PROVODKA SET CODE = 'TEMP' WHERE CODE = '20501'; | |
UPDATE PROVODKA SET CODE = '2501' WHERE CODE = '20502'; | |
UPDATE PROVODKA SET CODE = '2502' WHERE CODE = 'TEMP'; | |
-- Count days of week in a given year | |
WITH RECURSIVE alldays(theday) AS ( | |
SELECT date '2018-01-01' -- Seed Row | |
UNION ALL | |
SELECT theday + interval 1 day -- Recursion | |
FROM alldays | |
WHERE v < date '2019-01-01' | |
) | |
SELECT dayofweek, COUNT(*) | |
FROM (SELECT to_char(theday, 'day') AS dayofweek FROM alldays) | |
GROUP BY dayofweek; | |
-- SQLite version: | |
WITH RECURSIVE alldays(theday) AS ( | |
SELECT date('2018-01-01') UNION ALL | |
SELECT date(theday, '+1 day') newday FROM alldays WHERE newday<'2019-01-01') | |
SELECT strftime('%w',theday) dow, COUNT(*) | |
FROM alldays | |
GROUP BY dow; |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment