Splunk deployment based on CIDR

cidr2regex.py

#!/usr/bin/env python
''' Splunk deployment based on CIDR

Splunk's deployment server does not support CIDR based matching out of the box,
but they do support PCRE regex matching.  I found this script online and
modified it slightly to match Splunk's specific regex variation.  (Basically,
Splunk uses standards PCRE but replace the meaning of "." and "*" to act more
like traditional glob strings.)  The values returned by this script can be
used in the serverclass.conf for either whitelist.<n> or blacklist.<n> values.
See the Splunk docs for more details.

Example usage:
	echo "10.0.1.0/22" | python cidr2regex.py

Example output:
	^10.0.[0-3].\d+$


Original cidr2regex.py script:
	https://gist.github.com/tom-knight/1b5e0dcf39062af8910e

Thanks to github users:
	petermblair, 2xyo, mordyovits, tom-knight

Splunk docs:
	http://docs.splunk.com/Documentation/Splunk/latest/Admin/Serverclassconf

'''

import sys
from math import log10

def cidr_to_regex(cidr):
    ip, prefix = cidr.split('/')
 
    base = 0
    for val in map(int, ip.split('.')):
        base = (base << 8) | val

    shift = 32 - int(prefix)
    start = base >> shift << shift
    end = start | (1 << shift) - 1
 
    def regex(lower, upper):
        if lower == upper:
            return str(lower) 
        
        exp = int(log10(upper - lower))
	if (int(str(lower)[-1]) > int(str(upper)[-1]) and exp == 0):
            # increasing exp due to base 10 wrap to next exp
            exp += 1
        delta = 10 ** exp

        if lower == 0 and upper == 255:
            return "\d+"

        if delta == 1:
            val = ""
            for a, b in zip(str(lower), str(upper)):
                if a == b:
                    val += str(a)
                elif (a, b) == ("0", "9"):
                    val += '\d'
                elif int(b) - int(a) == 1:
                    val += '[%s%s]' % (a, b)
                else:
                    val += '[%s-%s]' % (a, b)
            return val
 
        def gen_classes():
            def floor_(x):
		return int(round(x / delta, 0) * delta)

            xs = range(floor_(upper) - delta, floor_(lower), -delta)
            for x in map(str, xs):
                yield '%s%s' % (x[:-exp], r'\d' * exp)

            yield regex(lower, floor_(lower) + (delta - 1))
            yield regex(floor_(upper), upper)
        return "(%s)" % '|'.join(gen_classes())
 
    def get_parts():
        for x in range(24, -1, -8):
            yield regex(start >> x & 255, end >> x & 255)

    # Not using the typical r'\.' regex because Splunk automatically 
    # replaces "." with "\." for the whitelist and blacklist entries.
    return '^%s$' % '.'.join(get_parts())

for line in sys.stdin.readlines():
	print cidr_to_regex( line )
	print

Unable to run the code, give the error "inconsistent use of tabs and spaces in indentation". I did few things to correct indentation, but still issues. Appreciate if you could have a look, it will be greatly useful

same here !!!