Created
May 24, 2014 15:02
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A template conundrum
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#include <string> | |
#include <iostream> | |
#include <functional> | |
using std::cout; | |
using std::endl; | |
template<typename return_type, typename ...params> | |
auto _L( return_type (*fp) (params... args)) | |
{ return [fp] (params... args) { return fp(args...); }; }; | |
template<typename return_type, typename argument_type> | |
auto _LL( return_type (*fp) (argument_type) ) | |
{ return [fp] (argument_type x) { return fp(x); }; }; | |
template<typename return_type, typename arg1_type, typename arg2_type> | |
auto _LL( return_type (*fp) (arg1_type, arg2_type) ) | |
{ return [=] (arg1_type x) | |
{ return [=] (arg2_type y) { return fp(x,y); }; }; | |
}; | |
int sub1(int x) { return x-1; } | |
double div(double x, double y) { return x/y; } | |
int main() | |
{ | |
// bar and baz both work as expected | |
// | |
auto bar = _L(sub1); | |
cout << bar(1) << endl; // prints 0 | |
auto baz = _LL(sub1); | |
cout << baz(1) << endl; // prints 0 | |
// foo and doof both fail, with error | |
// couldn't infer template argument 'return_type' | |
auto foo = _L(div); | |
cout << foo(4.0,3.0) << endl; | |
auto doof = _LL(div); | |
cout << doof(11.0)(10.0) << endl; | |
} |
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