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[Bash] How to exit the parent script if a child die? Call "./child.sh || exit 1" from the parent. Here an example:
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#!/bin/bash | |
## LICENSE | |
## Copyright (c) 2017, Luca Bertolasi. All Rights Reserved. | |
## | |
## This source code is licensed under the terms of the MIT license, | |
## a copy of which can be found at https://choosealicense.com/licenses/mit/ | |
cat << EOF > $(pwd)/parent.sh | |
#!/bin/bash | |
echo parent...start child_success | |
echo | |
./child_success.sh || exit 1 ## this line will succeed and not affect execution | |
echo | |
echo parent...start child_failure | |
echo | |
./child_failure.sh || exit 1 ## this line will fail and make the parent exit immediately | |
echo | |
echo parent...end | |
EOF | |
cat << EOF > $(pwd)/child_success.sh | |
#!/bin/bash | |
echo child_success...start | |
echo child_success...success | |
echo child_success...end | |
EOF | |
cat << EOF > $(pwd)/child_failure.sh | |
#!/bin/bash | |
echo child_failure...start | |
echo child_failure...failure | |
exit 1 ## here we are simulating a command that will fail and exit with code 1, making the parent exit immediately | |
echo child_failure...end | |
EOF | |
chmod u+x $(pwd)/parent.sh $(pwd)/child_success.sh $(pwd)/child_failure.sh | |
./parent.sh |
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