Difference between 2 dicts

diff_dicts.py

def diff_dicts(
    d1: dict,
    d2: dict,
    path: str = ""
) -> list[str]:

    diffs = []

    keys = set(d1.keys()) | set(d2.keys())

    for key in keys:
        current_path = f"{path}.{key}" if path else str(key)

        if key not in d1:
            diffs.append(
                f"Keys missing in first dict: {current_path}"
            )
            continue

        if key not in d2:
            diffs.append(
                f"Keys missing in second dict: {current_path}"
            )
            continue

        v1 = d1[key]
        v2 = d2[key]

        # Nested dict
        if isinstance(v1, dict) and isinstance(v2, dict):
            diffs.extend(
                diff_dicts(v1, v2, current_path)
            )

        # List
        elif isinstance(v1, list) and isinstance(v2, list):
            if len(v1) != len(v2):
                diffs.append(
                    f"Different length in {current_path}: "
                    f"{len(v1)} != {len(v2)}"
                )
                continue

            for index, (item1, item2) in enumerate(zip(v1, v2)):
                item_path = f"{current_path}[{index}]"

                if isinstance(item1, dict) and isinstance(item2, dict):
                    diffs.extend(
                        diff_dicts(item1, item2, item_path)
                    )
                elif item1 != item2:
                    diffs.append(
                        f"Different value in {item_path}: "
                        f"{item1!r} != {item2!r}"
                    )

        # Simple value
        elif v1 != v2:
            diffs.append(
                f"Different value in {current_path}: "
                f"{v1!r} != {v2!r}"
            )

    return diffs