Assignment 3

a3.py

'''A board is a list of list of str. For example, the board
    ANTT
    XSOB
is represented as the list
    [['A', 'N', 'T', 'T'], ['X', 'S', 'O', 'B']]

A word list is a list of str. For example, the list of words
    ANT
    BOX
    SOB
    TO
is represented as the list
    ['ANT', 'BOX', 'SOB', 'TO']
'''


def is_valid_word(wordlist, word):
    ''' (list of str, str) -> bool

    Return True if and only if word is an element of wordlist.

    >>> is_valid_word(['ANT', 'BOX', 'SOB', 'TO'], 'TO')
    True
    '''
    if word in wordlist:
        return True
    else:
        return False


def make_str_from_row(board, row_index):
    ''' (list of list of str, int) -> str

    Return the characters from the row of the board with index row_index
    as a single string.

    >>> make_str_from_row([['A', 'N', 'T', 'T'], ['X', 'S', 'O', 'B']], 0)
    'ANTT'
    '''
    row = board[row_index]
    result_word = ''
    for char in row:
        result_word = result_word + char
    return result_word


def make_str_from_column(board, column_index):
    ''' (list of list of str, int) -> str

    Return the characters from the column of the board with index column_index
    as a single string.

    >>> make_str_from_column([['A', 'N', 'T', 'T'], ['X', 'S', 'O', 'B']], 1)
    'NS'
    '''
    r_word = ''

    for i in board:
        r_word = r_word + i[column_index]

    return r_word

def board_contains_word_in_row(board, word):
    ''' (list of list of str, str) -> bool

    Return True if and only if one or more of the rows of the board contains
    word.

    Precondition: board has at least one row and one column, and word is a
    valid word.

    >>> board_contains_word_in_row([['A', 'N', 'T', 'T'], ['X', 'S', 'O', 'B']], 'SOB')
    True
    '''

    for row_index in range(len(board)):
        if word in make_str_from_row(board, row_index):
            return True

    return False


def board_contains_word_in_column(board, word):
    ''' (list of list of str, str) -> bool

    Return True if and only if one or more of the columns of the board
    contains word.

    Precondition: board has at least one row and one column, and word is a
    valid word.

    >>> board_contains_word_in_column([['A', 'N', 'T', 'T'], ['X', 'S', 'O', 'B']], 'NO')
    False
    '''
    i = 0
    while i < len(board[0]):
        if word in make_str_from_column(board, i):
            return True
        i = i + 1

    return False


def board_contains_word(board, word):
    '''(list of list of str, str) -> bool

    Return True if and only if word appears in board.

    Precondition: board has at least one row and one column.

    >>> board_contains_word([['A', 'N', 'T', 'T'], ['X', 'S', 'O', 'B']], 'ANT')
    True
    '''
    if(board_contains_word_in_column(board, word)):
        return True
    elif(board_contains_word_in_row(board, word)):
        return True

    return False


def word_score(word):
    '''(str) -> int

    Return the point value the word earns.

    Word length: < 3: 0 points
                 3-6: 1 point per character in word
                 7-9: 2 points per character in word
                 10+: 3 points per character in word

    >>> word_score('DRUDGERY')
    16
    '''
    word_len = len(word)
    if(word_len >= 10):
        return 3*word_len
    elif(word_len >= 7 and word_len <= 9):
        return 2*word_len
    elif(word_len >= 3 and word_len <= 6):
        return 1*word_len
    else:
        return 0

def update_score(player_info, word):
    '''([str, int] list, str) -> NoneType

    player_info is a list with the player's name and score. Update player_info
    by adding the point value word earns to the player's score.

    >>> update_score(['Jonathan', 4], 'ANT')
    '''
    player_info[1] = player_info[1] + word_score(word)

def num_words_on_board(board, words):
    '''(list of list of str, list of str) -> int

    Return how many words appear on board.

    >>> num_words_on_board([['A', 'N', 'T', 'T'], ['X', 'S', 'O', 'B']], ['ANT', 'BOX', 'SOB', 'TO'])
    3
    '''
    num_words = 0
    for word in words:
        if board_contains_word_in_column(board, word) == True:
            num_words += 1
        if board_contains_word_in_row(board, word) == True:
            num_words += 1

    return num_words


def read_words(words_file):
    ''' (file open for reading) -> list of str

    Return a list of all words (with newlines removed) from open file
    words_file.

    Precondition: Each line of the file contains a word in uppercase characters
    from the standard English alphabet.
    '''
    words_file2 = [item.rstrip() for item in words_file]
    return words_file2


def read_board(board_file):
    ''' (file open for reading) -> list of list of str

    Return a board read from open file board_file. The board file will contain
    one row of the board per line. Newlines are not included in the board.
    '''
    result = []
    line = board_file.readline()
    while line != '':
        in_result = []
        line=line.rstrip('\n')
 
        for letter in line:
            in_result.append(letter)
 
        result.append(in_result)    
        line = board_file.readline()
 
    return result


    

For is_valid_word, you can just use: return word in word_list, since word_in_word_list evaluates to a Boolean. A style thing more than anything, but you don't need to do an if/else test.