Shell - Get latest release from GitHub

get_latest_release.sh

get_latest_release() {
  curl --silent "https://api.github.com/repos/$1/releases/latest" | # Get latest release from GitHub api
    grep '"tag_name":' |                                            # Get tag line
    sed -E 's/.*"([^"]+)".*/\1/'                                    # Pluck JSON value
}

# Usage
# $ get_latest_release "creationix/nvm"
# v0.31.4

With the last update, the above breaks for me. I'm now using this:

latest_version_raw="$(curl -s https://api.github.com/repos/$owner_repo/releases | grep -m 1 "html_url" | rev | cut -    d/ -f1 | rev  )"
latest_version="${latest_version_raw%??}" # remove last 2 characters

Here's an example with wget & jq:

REPO="..."
VERSION=$(wget -q -O- https://api.github.com/repos/${REPO}/releases/latest | jq -r '.name')

Here's an example with wget & jq:

REPO="..."
VERSION=$(wget -q -O- https://api.github.com/repos/${REPO}/releases/latest | jq -r '.name')

that works great! but if prefer tag name instead of release name, use:

.tag_name

for how todo this on GitLab site, see my gist here:
https://gist.github.com/roelds/b2cd9cc2ba6c7887ddaf6bde2ef7ef50

One-liner using only curl + grep:
curl --silent "https://api.github.com/repos/${REPO}/releases/latest" | grep -Po "(?<=\"tag_name\": \").*(?=\")"

For the gh-cli inclined:

gh release list --exclude-pre-releases --json tagName,isLatest --jq '.[] | select(.isLatest) | .tagName'