Created
June 20, 2013 03:18
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Given an array with n objects colored red, white or blue, sort them so that objects of the same color are adjacent, with the colors in the order red, white and blue. Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively. Note:
You are not suppose to use the library's sort function for this problem. F…
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| C++: | |
| class Solution { | |
| public: | |
| void sortColors(int A[], int n) { | |
| // Start typing your C/C++ solution below | |
| // DO NOT write int main() function | |
| int head=0; | |
| int tail=n-1; | |
| int cur=0; | |
| while(cur<=tail){ | |
| if(A[cur]==0){ | |
| if(cur>head) swap(A,head,cur); | |
| head++; | |
| cur++; | |
| }else if(A[cur]==2){ | |
| swap(A,cur,tail); | |
| tail--; | |
| }else if(A[cur]==1) cur++; | |
| } | |
| } | |
| void swap(int *A,int i,int j){ | |
| int temp=A[i]; | |
| A[i]=A[j]; | |
| A[j]=temp; | |
| } | |
| }; | |
| Java: | |
| public class Solution { | |
| public void sortColors(int[] A) { | |
| // Start typing your Java solution below | |
| // DO NOT write main() function | |
| int head=0; | |
| int tail=A.length-1; | |
| int cur=0; | |
| while(cur<=tail){ | |
| if(A[cur]==0){ | |
| if(cur>head) swap(A,head,cur); | |
| head++; | |
| cur++; | |
| }else if(A[cur]==2){ | |
| swap(A,cur,tail); | |
| tail--; | |
| }else if(A[cur]==1) cur++; | |
| } | |
| } | |
| public void swap(int[] A,int i,int j){ | |
| int temp=A[i]; | |
| A[i]=A[j]; | |
| A[j]=temp; | |
| } | |
| } |
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