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@luoxiaoxun
Created June 21, 2013 02:53
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Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place. Follow up: Did you use extra space? A straight forward solution using O(mn) space is probably a bad idea. A simple improvement uses O(m + n) space, but still not the best solution. Could you devise a constant space solution?
C++:
class Solution {
public:
void setZeroes(vector<vector<int> > &matrix) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
bool row=false;
bool col=false;
for(int i=0;i<matrix.size();i++)
if(matrix[i][0]==0){
row=true;
break;
}
for(int j=0;j<matrix[0].size();j++)
if(matrix[0][j]==0){
col=true;
break;
}
for(int i=0;i<matrix.size();i++)
for(int j=0;j<matrix[0].size();j++)
if(matrix[i][j]==0){
matrix[i][0]=0;
matrix[0][j]=0;
}
for(int i=1;i<matrix.size();i++)
if(matrix[i][0]==0)
for(int j=0;j<matrix[0].size();j++)
matrix[i][j]=0;
for(int j=1;j<matrix[0].size();j++)
if(matrix[0][j]==0)
for(int i=0;i<matrix.size();i++)
matrix[i][j]=0;
if(row)
for(int i=0;i<matrix.size();i++)
matrix[i][0]=0;
if(col)
for(int j=0;j<matrix[0].size();j++)
matrix[0][j]=0;
}
};
Java:
public class Solution {
public void setZeroes(int[][] matrix) {
// Start typing your Java solution below
// DO NOT write main() function
boolean row=false;
boolean col=false;
for(int i=0;i<matrix.length;i++)
if(matrix[i][0]==0){
row=true;
break;
}
for(int j=0;j<matrix[0].length;j++)
if(matrix[0][j]==0){
col=true;
break;
}
for(int i=0;i<matrix.length;i++)
for(int j=0;j<matrix[0].length;j++)
if(matrix[i][j]==0){
matrix[i][0]=0;
matrix[0][j]=0;
}
for(int i=1;i<matrix.length;i++)
if(matrix[i][0]==0)
for(int j=0;j<matrix[0].length;j++)
matrix[i][j]=0;
for(int j=1;j<matrix[0].length;j++)
if(matrix[0][j]==0)
for(int i=0;i<matrix.length;i++)
matrix[i][j]=0;
if(row)
for(int i=0;i<matrix.length;i++)
matrix[i][0]=0;
if(col)
for(int j=0;j<matrix[0].length;j++)
matrix[0][j]=0;
}
}
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