Created
July 7, 2013 08:26
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Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target. Note: Elements in a quadruplet (a,b,c,d) must be in non-descending order. (ie, a ? b ? c ? d)
The solution set must not contain duplicate quadruplets. For example, given …
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| C++: | |
| class Solution { | |
| private: | |
| vector<vector<int>> ret; | |
| public: | |
| vector<vector<int> > fourSum(vector<int> &num, int target) { | |
| // Start typing your C/C++ solution below | |
| // DO NOT write int main() function | |
| ret.clear(); | |
| if(num.size()<4) return ret; | |
| sort(num.begin(),num.end()); | |
| vector<int> cur(4); | |
| for(int i=0;i<num.size()-3;i++){ | |
| for(int j=i+1;j<num.size()-2;j++){ | |
| int k=j+1; | |
| int t=num.size()-1; | |
| while(k<t){ | |
| if(num[i]+num[j]+num[k]+num[t]<target) k++; | |
| else if(num[i]+num[j]+num[k]+num[t]>target) t--; | |
| else{ | |
| cur[0]=num[i]; | |
| cur[1]=num[j]; | |
| cur[2]=num[k]; | |
| cur[3]=num[t]; | |
| ret.push_back(cur); | |
| k++; | |
| t--; | |
| } | |
| } | |
| } | |
| } | |
| sort(ret.begin(),ret.end()); | |
| ret.erase(unique(ret.begin(),ret.end()),ret.end()); | |
| return ret; | |
| } | |
| }; | |
| Java: | |
| public class Solution { | |
| public ArrayList<ArrayList<Integer>> fourSum(int[] num, int target) { | |
| // Start typing your Java solution below | |
| // DO NOT write main() function | |
| ArrayList<ArrayList<Integer>> ret=new ArrayList<ArrayList<Integer>>(); | |
| ArrayList<Integer> cur=new ArrayList<Integer>(); | |
| if(num.length<4) return ret; | |
| Arrays.sort(num); | |
| for(int i=0;i<num.length-3;i++){ | |
| for(int j=i+1;j<num.length-2;j++){ | |
| int k=j+1; | |
| int t=num.length-1; | |
| while(k<t){ | |
| if(num[i]+num[j]+num[k]+num[t]<target) k++; | |
| else if(num[i]+num[j]+num[k]+num[t]>target) t--; | |
| else{ | |
| cur.add(num[i]); | |
| cur.add(num[j]); | |
| cur.add(num[k]); | |
| cur.add(num[t]); | |
| if(!ret.contains(cur)){ | |
| ArrayList<Integer> temp=new ArrayList<Integer>(); | |
| for(Integer it:cur) temp.add(it); | |
| ret.add(temp); | |
| } | |
| cur.clear(); | |
| k++; | |
| t--; | |
| } | |
| } | |
| } | |
| } | |
| return ret; | |
| } | |
| } |
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