Created
July 8, 2013 08:10
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Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water. Note: You may not slant the container.
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| C++: | |
| class Solution { | |
| public: | |
| int maxArea(vector<int> &height) { | |
| // Start typing your C/C++ solution below | |
| // DO NOT write int main() function | |
| int low=0; | |
| int high=height.size()-1; | |
| int ret=0; | |
| while(low<high){ | |
| int area=(high-low)*min(height[low],height[high]); | |
| ret=max(ret,area); | |
| if(height[low]<=height[high]) low++; | |
| else high--; | |
| } | |
| return ret; | |
| } | |
| }; | |
| Java: | |
| public class Solution { | |
| public int maxArea(int[] height) { | |
| // Start typing your Java solution below | |
| // DO NOT write main() function | |
| int low=0; | |
| int high=height.length-1; | |
| int ret=0; | |
| while(low<high){ | |
| int area=(high-low)*Math.min(height[low],height[high]); | |
| ret=Math.max(ret,area); | |
| if(height[low]<=height[high]) low++; | |
| else high--; | |
| } | |
| return ret; | |
| } | |
| } |
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