Laravel Unit Testing with persistent SessionID

SessionTest.php

<?php

class ApiTest extends TestCase
{

    public function setUp()
    {
        parent::setUp();
        
        $this->session_id = session()->getId();
        $this->session_cookie = [session()->getName() => $this->session_id];
    }

    public function call($method, $uri, $parameters = [], $cookies = [], $files = [], $server = [], $content = null)
    {
        // set session_id cookie
        $cookies = array_merge($cookies, $this->session_cookie);
        parent::call($method, $uri, $parameters, $cookies, $files, $server, $content);
    }

    public function testSession() {
        // route return session()->getId()
        $this->get("/api/session/")
             ->seeStatusCode(200);

        $session_id = $this->response->original;

        $this->get("/api/session/")
             ->seeStatusCode(200)
             ->see($session_id);
    }

}

I found this pretty useful today, thanks for posting! A quick update though. About two years ago there was a withCookies method added to the MakesHttpRequests class. The concept above still works but you can do something like below now:

$this->withCookies($this->sessionCookie)->put(route('orders.update', $order['id']), ['item_id' => $this->additionalItem->id]);

The above example should return parent call in call() method otherwise returned response from the request will be null.

public function call($method, $uri, $parameters = [], $cookies = [], $files = [], $server = [], $content = null)
    {
        // set session_id cookie
        $cookies = array_merge($cookies, $this->session_cookie);
        return parent::call($method, $uri, $parameters, $cookies, $files, $server, $content);
    }