Checking the Existence of a C++ Class Member at Compile Time

has_member.hpp

// A compile-time method for checking the existence of a class member
// @see https://general-purpose.io/2017/03/10/checking-the-existence-of-a-cpp-class-member-at-compile-time/

// This code uses "decltype" which, according to http://en.cppreference.com/w/cpp/compiler_support
// should be supported by Clang 2.9+, GCC 4.3+ and MSVC 2010+ (if you have an older compiler, please upgrade :)
// As of "constexpr", if not supported by your compiler, you could try "const"
// or use the value as an inner enum value e.g. enum { value = ... }

// check "test_has_member.cpp" for a usage example

/// Defines a "has_member_member_name" class template
///
/// This template can be used to check if its "T" argument
/// has a data or function member called "member_name"
#define define_has_member(member_name)                                         \
    template <typename T>                                                      \
    class has_member_##member_name                                             \
    {                                                                          \
        typedef char yes_type;                                                 \
        typedef long no_type;                                                  \
        template <typename U> static yes_type test(decltype(&U::member_name)); \
        template <typename U> static no_type  test(...);                       \
    public:                                                                    \
        static constexpr bool value = sizeof(test<T>(0)) == sizeof(yes_type);  \
    }

/// Shorthand for testing if "class_" has a member called "member_name"
///
/// @note "define_has_member(member_name)" must be used
///       before calling "has_member(class_, member_name)"
#define has_member(class_, member_name)  has_member_##member_name<class_>::value

test_has_member.cpp

// usage example: check for the existence of a "sayHi" member //////////////////////////////////////

// clang++ -std=c++11 -pedantic -Wall -Wextra test_has_member.cpp -o test_has_member && ./test_has_member
// g++     -std=c++11 -pedantic -Wall -Wextra test_has_member.cpp -o test_has_member && ./test_has_member

#include <iostream> // cout, endl
#include <iomanip>  // std::boolalpha

#include "has_member.hpp"

struct A  // has a "sayHi" member
{
    void sayHi() { std::cout << "Hi there!" << std::endl;  }
};

struct B  // doesn't have a "sayHi" member
{
    void sayBye() { std::cout << "Bye bye!" << std::endl; }
};

// define a "sayHi" "member checker" class
define_has_member(sayHi);

int main()
{
    using std::cout;
    using std::endl;
    cout << std::boolalpha;  // display "true" or "false" for booleans

    A a;
    B b;

    // check the existence of "sayHi"
    cout << "has_member(A, sayHi) " << has_member(A, sayHi) << endl;
    cout << "has_member(B, sayHi) " << has_member(B, sayHi) << endl;

    cout << endl;

    // same thing, using decltype on instances
    cout << "has_member(decltype(a), sayHi) " << has_member(decltype(a), sayHi) << endl;
    cout << "has_member(decltype(b), sayHi) " << has_member(decltype(b), sayHi) << endl;

    return 0;
}

Is there a way to verify existence of private members too in c++?

Is it possible to check if A has a function sayHi(int)? basically check signature also.

Is it possible to check if A has a function sayHi(int)? basically check signature also.

I'm assuming you mean a way to disambiguate sayHi(float) from sayHi(int) or sayHi(string)

I believe this will only work if the signature is hinted at via a template (i.e. a function template on the member sayHi<T>(T)) because C++ gives no way to specify the overload except at the call site and the way yes_type is defined here is not going to do that. Perhaps there is a more convoluted way of defining yes_type to use std::declval so that the disambiguation can happen. At a first glance, it is not obvious.