Created
October 22, 2015 21:18
-
-
Save madrugado/6f808b655b9107be0658 to your computer and use it in GitHub Desktop.
The problem solved by this code is: we need to find a longest chain of substrings, where substring produced from string by dropping of one letter. The input reading is omitted.
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
#include <iostream> | |
#import <vector> | |
#import <string> | |
#import <set> | |
#import <algorithm> | |
#import <map> | |
using namespace std; | |
int main() { | |
vector<string> w; | |
sort(w.begin(), w.end(), [](const string& first, const string& second) {return first.size() < second.size();}); | |
set<string> s(w.begin(), w.end()); | |
map<string, set<string> > words; | |
for (auto&& str: w) { | |
for (unsigned j=0; j < str.length(); ++j) { | |
string temp = str.substr(0, j) + str.substr(j + 1); | |
if (s.find(temp) != s.end()) { | |
words[str].insert(temp); | |
} | |
} | |
} | |
map<string, unsigned > maxlen; | |
for (auto&& str: w) { | |
unsigned maxl = 0; | |
for (auto&&word: words[str]) { | |
if (maxl < maxlen[word] + 1) { | |
maxl = maxlen[word] + 1; | |
} | |
} | |
if (maxl != 0) { | |
maxlen[str] = maxl; | |
} else { | |
maxlen[str] = 0; | |
} | |
} | |
auto pr = std::max_element(maxlen.begin(), maxlen.end(), | |
[](const pair<string, unsigned>& p1, const pair<string, unsigned>& p2) { | |
return p1.second < p2.second; }); | |
cout << pr->first; | |
return 0; | |
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment