Replace field into column csv file bash script

replace-date-timestamp-date-csv.md

Replace field into column csv file bash script

First command is more faster than second

Exemple file

    1613667679,TXT,google.com,8.8.8.8,4,0,4,0,N/A,2,N/A
    1613667679,TXT,google.com,,8.8.8.8,4,0,4,0,N/A,2,N/A
    1613667679,TXT,google.com,,8.8.8.8,4,0,4,0,N/A,2,N/A

Replace timestamp to date first column

    sed -r 's#(([^0-9][0-9]{0,9})*)(\b[0-9]{10}\b)(([0-9]{0,9}[^0-9])*)#printf "%s%s%s" "\1" $(date -d@\3 "+%Y-%m-%d %H:%M:%S") "\4";#ge' /mnt/backup/file.csv > file.csv.t
    mv file.csv{.t,}

Replace timestamp to date first column

    IFS=,
    while read -ra a; do
            # delete double quote
            a="${a[0]//\"}"
            newDate=$(date +"%Y-%m-%d %H:%M:%S" -d @$a)
            a=$(echo "${a[0]}" | sed "s/${a[0]}/$newDate/");
            echo "${a[*]}";
    done < file.csv.csv > file.csv.t
    mv file.csv{.t,}