RGB to CIELab color space conversion

rgb2lab.py

# RGB to Lab conversion

# Step 1: RGB to XYZ
#         http://www.easyrgb.com/index.php?X=MATH&H=02#text2
# Step 2: XYZ to Lab
#         http://www.easyrgb.com/index.php?X=MATH&H=07#text7


def rgb2lab(inputColor):

    num = 0
    RGB = [0, 0, 0]

    for value in inputColor:
        value = float(value) / 255

        if value > 0.04045:
            value = ((value + 0.055) / 1.055) ** 2.4
        else:
            value = value / 12.92

        RGB[num] = value * 100
        num = num + 1

    XYZ = [0, 0, 0, ]

    X = RGB[0] * 0.4124 + RGB[1] * 0.3576 + RGB[2] * 0.1805
    Y = RGB[0] * 0.2126 + RGB[1] * 0.7152 + RGB[2] * 0.0722
    Z = RGB[0] * 0.0193 + RGB[1] * 0.1192 + RGB[2] * 0.9505
    XYZ[0] = round(X, 4)
    XYZ[1] = round(Y, 4)
    XYZ[2] = round(Z, 4)

    # Observer= 2°, Illuminant= D65
    XYZ[0] = float(XYZ[0]) / 95.047         # ref_X =  95.047
    XYZ[1] = float(XYZ[1]) / 100.0          # ref_Y = 100.000
    XYZ[2] = float(XYZ[2]) / 108.883        # ref_Z = 108.883

    num = 0
    for value in XYZ:

        if value > 0.008856:
            value = value ** (0.3333333333333333)
        else:
            value = (7.787 * value) + (16 / 116)

        XYZ[num] = value
        num = num + 1

    Lab = [0, 0, 0]

    L = (116 * XYZ[1]) - 16
    a = 500 * (XYZ[0] - XYZ[1])
    b = 200 * (XYZ[1] - XYZ[2])

    Lab[0] = round(L, 4)
    Lab[1] = round(a, 4)
    Lab[2] = round(b, 4)

    return Lab

Great. Any feedback @i-make-robots? :)

Your work is appreciated and I thank you. :)

Super helpful stuff! Just used the alg and values (hard to find in a digestible way) in c#

im gonna convert it to javascript for a module im making

@JayRizuri feel free to :D Thanks!

Thanks for that! In case this helps someone, I ported to JS as follow:

function rgb2lab_normalizeRgbChannel(channel) {
	channel /= 255;

	return 100 * (channel > 0.04045
		? Math.pow((channel + 0.055) / 1.055, 2.4)
		: channel / 12.92
	);
}

function rgb2lab_normalizeXyzChannel(channel) {
	return (channel > 0.008856)
		? Math.pow(channel, 1/3)
		: (7.787 * channel) + (16 / 116);
}

function rgb2lab([r, g, b]) {
	r = rgb2lab_normalizeRgbChannel(r);
	g = rgb2lab_normalizeRgbChannel(g);
	b = rgb2lab_normalizeRgbChannel(b);

	let X = r * 0.4124 + g * 0.3576 + b * 0.1805;
	let Y = r * 0.2126 + g * 0.7152 + b * 0.0722;
	let Z = r * 0.0193 + g * 0.1192 + b * 0.9505;

	// Observer= 2°, Illuminant= D65
	X = rgb2lab_normalizeXyzChannel(X / 95.0470);
	Y = rgb2lab_normalizeXyzChannel(Y / 100.0);
	Z = rgb2lab_normalizeXyzChannel(Z / 108.883);

	return [
		(116 * Y) - 16, // L
		500 * (X - Y),  // a
		200 * (Y - Z),  // b
	];
}

This is the code written in R.
I added a tiny extension, making the maximum of the RGB color value range variable instead of hard-coding it.

https://gist.github.com/TellAnAx/06ace666a92d0849d6b774de1790cc7a

rgb2lab <- function(inputColor, maxColorValue = 255){

    num <- 1
    RGB <- c(0, 0, 0)

    for(value in inputColor){    
      value <- value / maxColorValue

        if(value > 0.04045){
          value <- ((value + 0.055) / 1.055)^2.4
        } else{
          value <- value / 12.92
        }
          

        RGB[num] <- value * 100
        num <- num + 1
    }

    XYZ <- c(0, 0, 0)

    X = RGB[1] * 0.4124 + RGB[2] * 0.3576 + RGB[3] * 0.1805
    Y = RGB[1] * 0.2126 + RGB[2] * 0.7152 + RGB[3] * 0.0722
    Z = RGB[1] * 0.0193 + RGB[2] * 0.1192 + RGB[3] * 0.9505
    XYZ[1] = round(X, 4)
    XYZ[2] = round(Y, 4)
    XYZ[3] = round(Z, 4)

    # Observer= 2°, Illuminant= D65
    XYZ[1] = XYZ[1] / 95.047         # ref_X =  95.047
    XYZ[2] = XYZ[2] / 100.0          # ref_Y = 100.000
    XYZ[3] = XYZ[3] / 108.883        # ref_Z = 108.883

    num = 1
    for(value in XYZ){
            if(value > 0.008856){
            value = value ** (0.3333333333333333)  
            } else{
              value = (7.787 * value) + (16 / 116)
            }
      
        XYZ[num] <- value
        num <- num + 1  
    }



    Lab <- c(0, 0, 0)

    L = (116 * XYZ[2]) - 16
    a = 500 * (XYZ[1] - XYZ[2])
    b = 200 * (XYZ[2] - XYZ[3])

    Lab[1] = round(L, 4)
    Lab[2] = round(a, 4)
    Lab[3] = round(b, 4)

    return(Lab)
}

someome start a page on http://rosettacode.org/wiki/Rosetta_Code

Anyone have the numpy conversion for this code.. this takes too much time

This is really useful, thanks!