Wrote this program in 2003 to find google rank of a site given search items. Use it on your own risk.

googlerank.py

#! path to python
# copyright manu.datta gmail.com

import string
import getopt
import sys
import ConfigParser
import re

UsageErr ='googlerank -n <number> -d <website> -c <domain> <Search Word>'
cfg = ConfigParser.ConfigParser()
cfg.read('grank.ini')
sys.path.append(cfg.get('PyGoogle','HOME'))
import google
google.LICENSE_KEY=cfg.get('Google','KEY')
myargs = sys.argv[1:]
# split the args
optlist,args=getopt.getopt(myargs,'n:d:c:')
webSite=''
query=''
rtext=""
nums = 100
bWebSite = 0
# now send the google following query
#print optlist
for o,a in optlist:
    if(o=='-c'):
        rtext="country%s" % a.upper()
        #query=query+' site:'+a
    elif(o=='-d'):
        webSite = a
  #print 'WS'+webSite
	bWebSite = 1
    elif(o=='-n'):
        nums=int(a,10)
if bWebSite == 0:
    print 'Error: No Website specified'
    print UsageErr
    sys.exit(2)

searchWords=''
for words in args:
    searchWords = searchWords+' '+words
searchWords=searchWords[1:]
if searchWords=='':
    print 'Error: No Search Words'
    print UsageErr
    sys.exit(2)

query=query+' '+searchWords

left = nums
bThere = 0
counter = 0 
r=re.compile("^http://(.*)"+webSite+"/(.*)$")
while ( left > 0 and bThere==0):
    searchRes=google.doGoogleSearch(query,start=counter,restrict='%s' % rtext).results
    left = left - len(searchRes)
    for sites in searchRes:
        counter = counter + 1
        if r.match(sites.URL):
            print "%s is ranked %s for search terms:%s (restrict=%s)" % (webSite,str(counter),query,rtext)
            bThere = 1
            break

if ( bThere != 1):
    print "%s not ranked in first %s for search terms:%s (restrict=%s)" % (webSite,str(nums),query,rtext)