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fully recursive solution to the getMatrix function of the Knight's Dialer
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def getMatrix(matrix, turns): | |
""" | |
returns a matrix equal to the original matrix multiplied by itself a number of times euqal to the number of turns minus one | |
""" | |
if turns==1: | |
return matrix | |
else: | |
turnsBaseTwo = math.log(turns, 2) | |
if turnsBaseTwo.is_integer(): # recursive path 1 | |
tempMatrix = getMatrix(matrix, turns/2) # recursive path 1 | |
tempMatrixTwo = tempMatrix # recursive path 1 | |
else: # recursive path 2 | |
tempTurns = 2**math.floor(turnsBaseTwo) # recursive path 2 | |
tempTurnsTwo = turns - tempTurns # recursive path 2 | |
tempMatrix = getMatrix(matrix, tempTurns) # recursive path 2 | |
tempMatrixTwo = getMatrix(matrix, tempTurnsTwo) # recursive path 2 | |
return tempMatrix*tempMatrixTwo |
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