Created
October 28, 2011 03:53
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multivariate linear regression
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def feature_normalize(X): | |
''' | |
Returns a normalized version of X where | |
the mean value of each feature is 0 and the standard deviation | |
is 1. This is often a good preprocessing step to do when | |
working with learning algorithms. | |
''' | |
mean_r = [] | |
std_r = [] | |
X_norm = X | |
n_c = X.shape[1] | |
for i in range(n_c): | |
m = mean(X[:, i]) | |
s = std(X[:, i]) | |
mean_r.append(m) | |
std_r.append(s) | |
X_norm[:, i] = (X_norm[:, i] - m) / s | |
return X_norm, mean_r, std_r | |
def compute_cost(X, y, theta): | |
''' | |
Comput cost for linear regression | |
''' | |
#Number of training samples | |
m = y.size | |
predictions = X.dot(theta) | |
sqErrors = (predictions - y) | |
J = (1.0 / (2 * m)) * sqErrors.T.dot(sqErrors) | |
return J | |
def gradient_descent(X, y, theta, alpha, num_iters): | |
''' | |
Performs gradient descent to learn theta | |
by taking num_items gradient steps with learning | |
rate alpha | |
''' | |
m = y.size | |
J_history = zeros(shape=(num_iters, 1)) | |
for i in range(num_iters): | |
predictions = X.dot(theta) | |
theta_size = theta.size | |
for it in range(theta_size): | |
temp = X[:, it] | |
temp.shape = (m, 1) | |
errors_x1 = (predictions - y) * temp | |
theta[it][0] = theta[it][0] - alpha * (1.0 / m) * errors_x1.sum() | |
J_history[i, 0] = compute_cost(X, y, theta) | |
return theta, J_history |
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In the feature_normalize(X): you have an error:
instead of : X_norm = X
you should do: X_norm = X.xopy()