Created
May 6, 2016 20:47
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Simple PLINQ and LINQ Optimizer performance test
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var listSize = 10000000; | |
var stopwatch = new Stopwatch(); | |
stopwatch.Restart(); | |
var s = Enumerable.Range(1, listSize) | |
.Select(n => n * 2) | |
.Select(n => Math.Sin((2 * Math.PI * n)/1000)) | |
.Select(n => Math.Pow(n,2)) | |
.Sum(); | |
stopwatch.Stop(); | |
Console.WriteLine("LINQ {0} items in {1}ms", listSize, stopwatch.ElapsedMilliseconds); | |
stopwatch.Restart(); | |
double sum = 0; | |
for (int n = 1; n <= listSize; n++) | |
{ | |
var a = n * 2; | |
var b = Math.Sin((2 * Math.PI * a)/1000); | |
var c = Math.Pow(b,2); | |
sum += c; | |
} | |
stopwatch.Stop(); | |
Console.WriteLine("for loop {0} items in {1}ms", listSize, stopwatch.ElapsedMilliseconds); | |
var q = Enumerable.Range(1, listSize).AsQueryExpr() | |
.Select(n => n * 2) | |
.Select(n => Math.Sin((2 * Math.PI * n) / 1000)) | |
.Select(n => Math.Pow(n, 2)) | |
.Sum(); | |
q.Compile(); | |
stopwatch.Restart(); | |
var s2 = q.Run(); | |
stopwatch.Stop(); | |
Console.WriteLine("LinqOptimizer.CSharp {0} items in {1}ms", listSize, stopwatch.ElapsedMilliseconds); | |
stopwatch.Restart(); | |
var s3 = Enumerable.Range(1, listSize).AsParallel() | |
.Select(n => n * 2) | |
.Select(n => Math.Sin((2 * Math.PI * n) / 1000)) | |
.Select(n => Math.Pow(n, 2)) | |
.Sum(); | |
stopwatch.Stop(); | |
Console.WriteLine("PLINQ {0} items in {1}ms", listSize, stopwatch.ElapsedMilliseconds); |
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