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A simple tentative Ellipticoin Supply curve
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import datetime | |
import time | |
# All monetary values are in Ellipticoin Base Units (one onethousandth of an Ellipticoin) | |
YEARS_PER_ERA = 2 | |
NUMBER_OF_ERAS = 7 | |
SECONDS_PER_BLOCK = 5 | |
SECONDS_IN_A_YEAR = datetime.timedelta(days=365).total_seconds() | |
BLOCKS_PER_ERA = int(YEARS_PER_ERA * SECONDS_IN_A_YEAR)/ SECONDS_PER_BLOCK | |
LOG_BASE = 2 | |
SCALE = 10000 | |
LAUNCH_DATE = datetime.datetime(2019, 9, 1, 0, 0) | |
def reward_era(block_number): | |
return block_number / BLOCKS_PER_ERA | |
def reward_at_era(era): | |
return LOG_BASE**(NUMBER_OF_ERAS - era - 1) * SCALE | |
def block_number_to_date(block_number): | |
seconds = block_number * SECONDS_PER_BLOCK | |
date = LAUNCH_DATE + datetime.timedelta(seconds=seconds) | |
return date.strftime("%Y-%m-%d") | |
def total_supply_at(block_number): | |
total = 0 | |
for era in range(0, reward_era(block_number)): | |
total += reward_at_era(era) * BLOCKS_PER_ERA | |
return total | |
print "|Block Number| Date | Block Reward | Total Supply at end of period" | |
print "-------------------------------------------------------" | |
for block_number in range(0, (int(BLOCKS_PER_ERA * NUMBER_OF_ERAS)), | |
BLOCKS_PER_ERA): | |
date = block_number_to_date(block_number) | |
reward = reward_at_era(reward_era(block_number)) | |
total_supply = total_supply_at(block_number) | |
print("{:>12} | {} | {:>13} | {}".format(block_number, date, reward, | |
total_supply)) | |
# Output | |
# |Block Number| Date | Block Reward | Total Supply at end of period | |
# ------------------------------------------------------- | |
# 0 | 2019-09-01 | 640000 | 0 | |
# 12614400 | 2021-08-31 | 320000 | 8073216000000 | |
# 25228800 | 2023-08-31 | 160000 | 12109824000000 | |
# 37843200 | 2025-08-30 | 80000 | 14128128000000 | |
# 50457600 | 2027-08-30 | 40000 | 15137280000000 | |
# 63072000 | 2029-08-29 | 20000 | 15641856000000 | |
# 75686400 | 2031-08-29 | 10000 | 15894144000000 |
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