Mateja Petrovic mateja176

In all interactions and commit message be extremely concise and sacrifice grammar for the sake of concision.

Plans

At the end of each plan, give me a list of unresolved questions if any. Make the questions extremely concise. Sacrifice grammar for the sake of concision.

	const quickSort = (a: Array<number>): Array<number> => {
	if (a.length <= 1) {
	return a
	}
	const [n, ...ns] = a
	const { left, right } = ns.reduce<{ left: Array<number>; right: Array<number> }>(
	({ left: left1, right: right1 }, m) => {
	if (m > n) {
	return { left: left1, right: right1.concat(m) }
	}

	function christmasTree(n: number) {
	let padding = n - 1;
	for (let index = 1; index < n; index++) {
	const oddNumber = index * 2 - 1;
	console.log(' '.repeat(padding), '*'.repeat(oddNumber));

	padding -= 1;
	}
	}

	type A = { a: 1; b: 2 };
	type ObjectToArray<O> = {
	[Key in keyof O]: [Key, O[Key]];
	}[keyof O][];
	type B = ObjectToArray<A>;

	const entries = <O>(o: O): ObjectToArray<O> => {
	const a: ObjectToArray<O> = [];
	for (const key in o) {
	const element = o[key];

	const groupByProp = <P extends string, O extends { [Key in P]: string }>(
	objects: O[],
	prop: P,
	) => {
	return objects.reduce((groups, object) => {
	const key = object[prop];
	return { ...groups, [key]: (groups[key] ?? []).concat(object) };
	}, {} as Record<O[P], O[]>);
	};

	type RequiredKeys<O extends unknown> = {
	// eslint-disable-next-line @typescript-eslint/ban-types
	[Key in keyof O]: {} extends Pick<O, Key> ? never : Key;
	}[keyof O];

	type DeepPick<O extends unknown, Keys extends unknown[]> = Keys extends [
	keyof O,
	...infer Rest
	]
	? Keys[0] extends RequiredKeys<O>