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Django : Generate unique slug
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# import signals and slugify | |
from django.db.models import signals | |
from django.template.defaultfilters import slugify | |
class Post(models.Model): | |
text = models.TextField("Post text") | |
# function for use in pre_save | |
def post_pre_save(signal, instance, sender, **kwargs): | |
if not instance.slug: | |
slug = slugify(instance.attribute) # change the attibute to the field that would be used as a slug | |
new_slug = slug | |
count = 0 | |
while Post.objects.filter(slug=new_slug).exclude(id=instance.id).count() > 0: | |
count += 1 | |
new_slug = '{slug}-{count}'.format(slug=slug, count=count) | |
instance.slug = new_slug | |
# Execute signals pre_save | |
signals.pre_save.connect(post_pre_save, sender=Post) |
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@Radi85 Today I really think the best approach is use a
external_id
field with last parameter of URL instead the count on post save.e.g.