Created
January 4, 2014 03:34
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Find the color between any two color points through linear interpolation. Pretty basic & straight forward.
Progress bar demo at: http://jsfiddle.net/99ycK/1/
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Color = function(hexOrObject) { | |
var obj; | |
if (hexOrObject instanceof Object) { | |
obj = hexOrObject; | |
} else { | |
obj = LinearColorInterpolator.convertHexToRgb(hexOrObject); | |
} | |
this.r = obj.r; | |
this.g = obj.g; | |
this.b = obj.b; | |
} | |
Color.prototype.asRgbCss = function() { | |
return "rgb("+this.r+", "+this.g+", "+this.b+")"; | |
} | |
var LinearColorInterpolator = { | |
// convert 6-digit hex to rgb components; | |
// accepts with or without hash ("335577" or "#335577") | |
convertHexToRgb: function(hex) { | |
match = hex.replace(/#/,'').match(/.{1,2}/g); | |
return new Color({ | |
r: parseInt(match[0], 16), | |
g: parseInt(match[1], 16), | |
b: parseInt(match[2], 16) | |
}); | |
}, | |
// left and right are colors that you're aiming to find | |
// a color between. Percentage (0-100) indicates the ratio | |
// of right to left. Higher percentage means more right, | |
// lower means more left. | |
findColorBetween: function(left, right, percentage) { | |
newColor = {}; | |
components = ["r", "g", "b"]; | |
for (var i = 0; i < components.length; i++) { | |
c = components[i]; | |
newColor[c] = Math.round(left[c] + (right[c] - left[c]) * percentage / 100); | |
} | |
return new Color(newColor); | |
} | |
} | |
var l = new Color({ r:100, g:100, b:100 }); | |
var r = new Color("#ffaa33"); | |
var backgroundColor = LinearColorInterpolator.findColorBetween(l, r, 50).asRgbCss(); | |
// do something with backgroundColor... |
newColor[c] = Math.round(Math.sqrt((left[c]**2 + (right[c]**2 - left[c]**2) * percentage / 100));
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Awesome :)
just noting that this doesnt support colors like
new Color("#FFF")
(shorthand using only three wont set b channel).also theres no clamping of percentages here e.g. can send 1million percent and it will go past the r color