Write code to count the number of strings in list items that have the character w in it. Assign that number to the variable acc_num. HINT 1: Use the accumulation pattern! HINT 2: the in operator checks whether a substring is present in a string. Hard-coded answers will receive no credit.

countW.py

items = ["whirring", "wow!", "calendar", "wry", "glass", "", "llama","tumultuous","owing"]
count = 0
for i in items:
    if 'w' in i:
        count += 1
acc_num = count

it doesn't work

use if word.count("w") > 0:

items = ["whirring", "wow!", "calendar", "wry", "glass", "", "llama", "tumultuous", "owing"]

acc_num = 0
for character in items:
if "w" in character:
acc_num += 1
print(acc_num)

items = ["whirring", "wow!", "calendar", "wry", "glass", "", "llama","tumultuous","owing"]

acc_num=0
for y in items:
if (y.count("w"))>0:
acc_num+=1
print (acc_num)

items = ["whirring", "wow!", "calendar", "wry", "glass", "", "llama","tumultuous","owing"]
acc_num =0
for i in items:
if 'w' in i:
acc_num += 1
print(acc_num)

This works.