This example shows how to link nodes in a force-directed graph using a named identifier rather than a numeric index.
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March 13, 2023 22:04
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Link Nodes by Name
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license: gpl-3.0 |
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{ | |
"nodes": [ | |
{"id": "red"}, | |
{"id": "orange"}, | |
{"id": "yellow"}, | |
{"id": "green"}, | |
{"id": "blue"}, | |
{"id": "violet"} | |
], | |
"links": [ | |
{"source": "red", "target": "yellow"}, | |
{"source": "red", "target": "blue"}, | |
{"source": "red", "target": "green"} | |
] | |
} |
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<!DOCTYPE html> | |
<meta charset="utf-8"> | |
<style> | |
.node { | |
stroke: #000; | |
stroke-width: 1.5px; | |
} | |
.link { | |
stroke: #999; | |
stroke-width: 1.5px; | |
} | |
</style> | |
<svg width="960" height="500"></svg> | |
<script src="//d3js.org/d3.v4.min.js"></script> | |
<script> | |
var svg = d3.select("svg"), | |
width = +svg.attr("width"), | |
height = +svg.attr("height"); | |
var simulation = d3.forceSimulation() | |
.force("charge", d3.forceManyBody().strength(-200)) | |
.force("link", d3.forceLink().id(function(d) { return d.id; }).distance(40)) | |
.force("x", d3.forceX(width / 2)) | |
.force("y", d3.forceY(height / 2)) | |
.on("tick", ticked); | |
var link = svg.selectAll(".link"), | |
node = svg.selectAll(".node"); | |
d3.json("graph.json", function(error, graph) { | |
if (error) throw error; | |
simulation.nodes(graph.nodes); | |
simulation.force("link").links(graph.links); | |
link = link | |
.data(graph.links) | |
.enter().append("line") | |
.attr("class", "link"); | |
node = node | |
.data(graph.nodes) | |
.enter().append("circle") | |
.attr("class", "node") | |
.attr("r", 6) | |
.style("fill", function(d) { return d.id; }); | |
}); | |
function ticked() { | |
link.attr("x1", function(d) { return d.source.x; }) | |
.attr("y1", function(d) { return d.source.y; }) | |
.attr("x2", function(d) { return d.target.x; }) | |
.attr("y2", function(d) { return d.target.y; }); | |
node.attr("cx", function(d) { return d.x; }) | |
.attr("cy", function(d) { return d.y; }); | |
} | |
</script> |
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