Created
November 11, 2022 17:08
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My own simple, a word which hear means inefficient, implementation of humanize.Comma
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package humanize | |
import ( | |
"fmt" | |
"strings" | |
) | |
// Comma formats a number with commas separating each block of 3 numbers. | |
// Inspiration: https://pkg.go.dev/github.com/dustin/go-humanize#Comma | |
func Comma(n int) string { | |
s := []rune(Reverse(fmt.Sprint(n))) | |
var b strings.Builder | |
for x := 0; ; x++ { | |
b.WriteRune(s[0]) | |
s = s[1:] | |
if len(s) > 0 && (x+1)%3 == 0 { | |
b.WriteRune(',') | |
} | |
if len(s) == 0 { | |
return Reverse(b.String()) | |
} | |
} | |
} | |
func Reverse(s string) string { | |
runes := []rune(s) | |
for i, j := 0, len(runes)-1; i < j; i, j = i+1, j-1 { | |
runes[i], runes[j] = runes[j], runes[i] | |
} | |
return string(runes) | |
} |
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package humanize | |
import "testing" | |
func TestCommas(t *testing.T) { | |
assertEqual(t, "1", Comma(1)) | |
assertEqual(t, "10", Comma(10)) | |
assertEqual(t, "100", Comma(100)) | |
assertEqual(t, "1,000", Comma(1000)) | |
assertEqual(t, "10,000", Comma(10000)) | |
assertEqual(t, "100,000", Comma(100000)) | |
} | |
func assertEqual(t *testing.T, expected, actual string) { | |
if actual == expected { | |
return | |
} | |
t.Helper() | |
t.Errorf("\n"+ | |
"want [%s]"+"\n"+ | |
"got [%s]", actual, expected) | |
} |
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