Write a function that when passed an array of numbers it gives you the max difference between the largest and smallest number ONLY if the small number is in front of the large number, not behind it, so for example: [3,4,8,1] = 5, notice how the biggest difference is between 8 and 1, but because the 1 is after the 8 in the array it shouldn't cou…

caller.js

var arr = [3, 4, 8, 1];
console.log(sth(arr));

loop.js

function sth(arr) {
  var min = Number.MAX_VALUE;
  var diff = Number.MIN_VALUE;
  
  for (var i = 0; i < arr.length; i++) {
      var n = arr[i];
      
      diff = Math.max(diff, n - min);
      min = Math.min(min, n);
  }
  return diff;
}

reduce.js

function sth(arr) {
  var diff = Number.MIN_VALUE;
  
  arr.reduce(function(min, n) {
    diff = Math.max(diff, n - min);
    return Math.min(min, n);
    
  }, Number.MAX_VALUE);
  
  return diff;
}