packaging and unpackaging multiple implicit conversions in an HList

all.scala

object AllExamples extends App {
  import shapeless._

  final class All[L <: HList](val values: L) {
    def apply[A](implicit selector: Selector[L, A]): A = values.select[A]
  }

  object All {

    // package a value of type A, convertible to type B, into an HList containing just B
    implicit def toAll0[A, B](a: A)(implicit a2b: A => B): All[B :: HNil] =
      new All(a :: HNil)

    // package a value of type A, convertible to B and some other types L, into an HList containing B and all types in L
    implicit def toAll1[A, B, L <: _ :: _](a: A)(implicit a2b: A => B, a2l: A => All[L]): All[B :: L] =
      new All(a :: a.values)
  }

  // example data
  trait A { def a: String }
  trait B { def b: String }
  trait C { def c: String }

  implicit def intA(n: Int): A = new A { def a = "a " + n.toString }
  implicit def intB(n: Int): B = new B { def b = "b " + n.toString }
  implicit def intC(n: Int): C = new C { def c = "c " + n.toString }

  implicit def stringA(s: String): A = new A { def a = "a " + s }
  implicit def stringB(s: String): B = new B { def b = "b " + s }
  implicit def stringC(s: String): C = new C { def c = "c " + s }

  // implicitly convert int and string values to A, B and Cs
  val abcs: Seq[All[A :: B :: C :: HNil]] = Seq(1, "haha", 2, "hoho")

  // unpack
  for (abc <- abcs) {
    println(abc[A].a)
    println(abc[B].b)
    println(abc[C].c)
  }
}

Yes, exactly that. Sorry I confused things by mentioning conversions ... I was playing around with something which tried to use a conversion from All[... T ...] to T which got bitten by exactly the same problem.

In my Pack case things are a bit different: the additional structure in the result type (due to the outer type constructor) seems to be enough to allow the inference/resolution to go through. I think having a single argument list with multiple Packs at different type constructors will probably work, but I haven't checked.