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@mgritter
Created January 28, 2024 08:16
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An analysis of dice mechanism by Elias Barry
outcomes = ["AS", "AF", "NS", "NF", "DS", "DF"]
# Game played with N-sided dice
# Player may reroll R times
# Success threshold is max of D dice.
def prob(N, R, D):
P = {}
EV = {}
advantage = range( 2 * N // 3 + 1, N+1 )
disadvantage = range( 1, N // 3 + 1 )
neutral = range( N // 3 + 1, 2 * N // 3 + 1 )
for a in range( 1, N+1 ):
pS = (a * 1.0 / N) ** D
pF = 1.0 - pS
for b in range( 1, N+1 ):
for o in outcomes:
P[(o,a,b,0)] = 0.0
if b in advantage:
P[("AS",a,b,0)] = pS
P[("AF",a,b,0)] = pF
elif b in disadvantage:
P[("DS",a,b,0)] = pS
P[("DF",a,b,0)] = pF
else:
P[("NS",a,b,0)] = pS
P[("NF",a,b,0)] = pF
for r in range( 1, R+1 ):
for a in range(1,N+1):
for b in range(1,N+1):
EV[(a,b,r-1)] = \
4 * P[("AS",a,b,r-1)] + \
3 * P[("NS",a,b,r-1)] + \
2 * P[("DS",a,b,r-1)] + \
2 * P[("AF",a,b,r-1)] + \
1 * P[("NF",a,b,r-1)]
for b in range( 1, N+1 ):
#print( f"EV[*,{b},{r-1}] = 1/{N} * (", end='' )
#for a in range(1, N+1):
# print( f"{EV[(a,b,r-1)]} + ", end='' )
#print( ")")
EV[("*",b,r-1)] = sum(EV[(a,b,r-1)] for a in range(1,N+1)) / N
for a in range(1,N+1):
for b in range(1,N+1):
# if EV( a, b, 0 ) < EV( *, a, r-1 ) then reroll
if EV[(a,b,0)] < EV[("*",a,r-1)]:
#print( f'{a},{b} {r} {EV[(a,b,0)]} vs {EV[("*",a,r-1)]} reroll' )
# Reroll moves a to b and replaces a with unform outcome [1,N]
for o in outcomes:
P[(o,a,b,r)] = sum( P[(o,k,a,r-1)] for k in range(1,N+1) ) / N
else:
#print( f'{a},{b} {r} {EV[(a,b,0)]} vs {EV[("*",a,r-1)]} stop' )
for o in outcomes:
P[(o,a,b,r)] = P[(o,a,b,0)]
# Initial state probabilities
init = {}
for o in outcomes:
init[o] = sum( P[(o,a,b,R)]
for a in range(1,N+1)
for b in range(1,N+1) ) / (N ** 2)
return init, P, EV
def show_decision(N, r, EV):
print( f"[{r} rerolls left]" )
print( "a\\b " + " ".join( str(x) for x in range(1,N+1) ) )
for a in range( 1, N+1):
print( f"{a:3} ", end='')
for b in range(1, N+1):
if EV[(a,b,0)] < EV[("*",a,r-1)]:
print( "R ", end='')
else:
print( "x ", end='')
print()
def main():
N = 6
R = 10
for D in range(1,11):
print( f"### Difficulty {D}")
init, p, ev = prob(N, R, D)
for o in outcomes:
print( f"{o} {init[o]}" )
print()
for r in range(1, R+1):
show_decision(N, r, ev)
print()
if __name__ == "__main__":
main()
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